A hydrogen atom in its ground state is irradiated by light of wavelength 970 mathringA. Taking hc / e =1.237 × 10-6 eV m and the ground state energy of hydrogen atom as -13.6 eV, the number of lines present in the emission spectrum is.

Question

A hydrogen atom in its ground state is irradiated by light of wavelength 970 mathringA. Taking hc / e =1.237 × 10-6 eV m and the ground state energy of hydrogen atom as -13.6 eV, the number of lines present in the emission spectrum is. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Z=1 n=1 λ=970 E=(12400 eV /970)=12.75 eV Energy difference between n =1 n =4 So electron transit to n =4 ∴ no. of lines in emission spectrum =(n(n-1)/2)=(4(4-1)/2)=6

Q. A hydrogen atom in its ground state is irradiated by light of wavelength $970 \overset{˚}{A}$ . Taking $h c / e = 1.237 \times 1 0^{- 6} e Vm$ and the ground state energy of hydrogen atom as $- 13.6 e V$ , the number of lines present in the emission spectrum is.

$Z = 1$
$n = 1$
$λ = 970$
$E = \frac{12400 e V}{970} = 12.75 e V$
Energy difference between $n = 1& n = 4$
So electron transit to $n = 4$
$∴$ no. of lines in emission spectrum
$= \frac{n ( n - 1 )}{2} = \frac{4 ( 4 - 1 )}{2} = 6$

Q. A hydrogen atom in its ground state is irradiated by light of wavelength 970A˚. Taking hc/e=1.237×10−6eVm and the ground state energy of hydrogen atom as −13.6eV, the number of lines present in the emission spectrum is.

Z=1 n=1 λ=970 E=97012400eV​=12.75eV Energy difference between n=1&n=4 So electron transit to n=4 ∴ no. of lines in emission spectrum =2n(n−1)​=24(4−1)​=6

Q. A hydrogen atom in its ground state is irradiated by light of wavelength $970 \overset{˚}{A}$ . Taking $h c / e = 1.237 \times 1 0^{- 6} e Vm$ and the ground state energy of hydrogen atom as $- 13.6 e V$ , the number of lines present in the emission spectrum is.

$Z = 1$
$n = 1$
$λ = 970$
$E = \frac{12400 e V}{970} = 12.75 e V$
Energy difference between $n = 1& n = 4$
So electron transit to $n = 4$
$∴$ no. of lines in emission spectrum
$= \frac{n ( n - 1 )}{2} = \frac{4 ( 4 - 1 )}{2} = 6$