A hydrocarbon C x H y undergoes complete combustion with required amount of oxygen to produce CO 2 and H 2 O. If the ratio of masses of hydrocarbon burnt to oxygen gas consumed comes out to be 29: 104, then value of (x+y) is :

Question

A hydrocarbon C x H y undergoes complete combustion with required amount of oxygen to produce CO 2 and H 2 O. If the ratio of masses of hydrocarbon burnt to oxygen gas consumed comes out to be 29: 104, then value of (x+y) is : (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Hydrocarbon C x H text y undergoes complete combustion according to the balanced chemical equation: C x H y +(x+(y/4)) O 2 longrightarrow CO 2+(y/2) H 2 O From the above equation, it is clear that: ( text Mass of C x H y text burnt / text Mass of O 2 text consumed )=(12 x+y/(x+(y)4) 32) But, this ratio is given as 29: 104. ∴ (12 x+y/(x+(y)4) 32)=(29/104) On solving, we get x: y=2: 5. But, there exists no hydrocarbon with formula C 2 H 5. ∴ Molecular formula of hydrocarbon is C 4 H 10 ∴ x=4, y=10

Q. A hydrocarbon Cx​Hy​ undergoes complete combustion with required amount of oxygen to produce CO2​ and H2​O. If the ratio of masses of hydrocarbon burnt to oxygen gas consumed comes out to be 29:104, then value of (x+y) is :

Q. A hydrocarbon $C_{x} H_{y}$ undergoes complete combustion with required amount of oxygen to produce $C O_{2}$ and $H_{2} O$ . If the ratio of masses of hydrocarbon burnt to oxygen gas consumed comes out to be $29 : 104$ , then value of $(x + y)$ is :