A hollow sphere of mass 1 kg and radius 10 cm is free to rotate about its diameter. If a force of 30 N is applied tangentially to it, its angular acceleration is (in rad / s 2 )

Question

A hollow sphere of mass 1 kg and radius 10 cm is free to rotate about its diameter. If a force of 30 N is applied tangentially to it, its angular acceleration is (in rad / s 2 ) (A) 5000 (B) 450 (C) 50 (D) 5

Tardigrade Admin · Accepted Answer

Use τ=I α 30((10/100))=(2/3)(1)((10/100))2 α α=450 rad / s 2

Q. A hollow sphere of mass $1 k g$ and radius $10 c m$ is free to rotate about its diameter. If a force of $30 N$ is applied tangentially to it, its angular acceleration is (in $r a d / s^{2}$ )

5000

450

50

5

Use $τ = I α$
$30 (\frac{10}{100}) = \frac{2}{3} (1) (\frac{10}{100})^{2} α$
$α = 450 r a d / s^{2}$

Q. A hollow sphere of mass 1kg and radius 10cm is free to rotate about its diameter. If a force of 30N is applied tangentially to it, its angular acceleration is (in rad/s2 )

5000

450

50

5

Use τ=Iα 30(10010​)=32​(1)(10010​)2α α=450rad/s2

Q. A hollow sphere of mass $1 k g$ and radius $10 c m$ is free to rotate about its diameter. If a force of $30 N$ is applied tangentially to it, its angular acceleration is (in $r a d / s^{2}$ )

Use $τ = I α$
$30 (\frac{10}{100}) = \frac{2}{3} (1) (\frac{10}{100})^{2} α$
$α = 450 r a d / s^{2}$