A heavy mass is attached to a thin wire and is whireled in a vertical circle. The wire is most likely to break

Question

A heavy mass is attached to a thin wire and is whireled in a vertical circle. The wire is most likely to break (A) When the mass is at the lowest point (B) When mass is at the highest point (C) When wire is horizontal (D) When mass is at an angle of cos-1((1/√2)) from upward vertical

Tardigrade Admin · Accepted Answer

When the mass is at the lowest point.
Explanation

\Rightarrow

The Force acting on the Particles will be maximum in case of the Vertical circle when the Force acting will be in the direction of its tension force of string.
When this situation arises then,
Tension

(T) = \frac{m v ^{2}}{r}

∴

Force will be maximum at this position and there will likely be more chances to break.
This case will be there when the mass is at the lowest position.

Q. A heavy mass is attached to a thin wire and is whireled in a vertical circle. The wire is most likely to break

When the mass is at the lowest point

When mass is at the highest point

When wire is horizontal

When mass is at an angle of $cos^{- 1} (\frac{1}{2})$ from upward vertical

Q. A heavy mass is attached to a thin wire and is whireled in a vertical circle. The wire is most likely to break

When the mass is at the lowest point

When mass is at the highest point

When wire is horizontal

When mass is at an angle of cos−1(2​1​) from upward vertical

When mass is at an angle of $cos^{- 1} (\frac{1}{2})$ from upward vertical