A heating curve has been plotted for a solid object as shown in the figure. If the mass of the object is 100 g , then latent heat of vapourisation for the material of the object is [Given, power supplied to the object is constant and equal to 1 kW ]

Question

A heating curve has been plotted for a solid object as shown in the figure. If the mass of the object is 100 g , then latent heat of vapourisation for the material of the object is [Given, power supplied to the object is constant and equal to 1 kW ] <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-iqjffihbiazl.png" /> (A) 1.5× 106 J / k g (B) 2.5× 106 J / k g (C) 3.5× 106 J / k g (D) 9.0× 106 J / k g

Tardigrade Admin · Accepted Answer

The total heat supplied to the block is displaystyle ∫ 16002500pdt=mLv 1000× (2500 - 1600)=0.1Lv Lv=9.0× 106J/kg

Q. A heating curve has been plotted for a solid object as shown in the figure. If the mass of the object is $100 g$ , then latent heat of vapourisation for the material of the object is [Given, power supplied to the object is constant and equal to $1 kW$ ]

$1.5 \times 1 0^{6} J / k g$

$2.5 \times 1 0^{6} J / k g$

$3.5 \times 1 0^{6} J / k g$

$9.0 \times 1 0^{6} J / k g$

The total heat supplied to the block is
$\int_{1600}^{2500} p d t = m L_{v}$
$1000 \times (2500 - 1600) = 0.1 L_{v}$
$L_{v} = 9.0 \times 1 0^{6} J / k g$

Q. A heating curve has been plotted for a solid object as shown in the figure. If the mass of the object is 100g , then latent heat of vapourisation for the material of the object is [Given, power supplied to the object is constant and equal to 1kW ]

1.5×106J/kg

2.5×106J/kg

3.5×106J/kg

9.0×106J/kg