A glass flask of volume 1000 cm3 is completely filled with mercury at 0° C. The co-efficient of cubical expansion of mercury is 180 × 10-6/ ° C and that of glass is 30×10-6 /° C. If the flask is now placed in boiling water at 100 ° C, how much mercury will over flow ?

Question

A glass flask of volume 1000 cm3 is completely filled with mercury at 0° C. The co-efficient of cubical expansion of mercury is 180 × 10-6/ ° C and that of glass is 30×10-6 /° C. If the flask is now placed in boiling water at 100 ° C, how much mercury will over flow ? (A) 30 cm3 (B) 18.0 cm3 (C) 15.0 cm3 (D)  3 cm3.

Tardigrade Admin · Accepted Answer

&gamma;a=&gamma;r-&gamma;g=(180-30)×10-6=150×10-5/° C Δ V=V0&gamma;Δ t=1000×150×10-5×100

$30 c m^{3}$

$18.0 c m^{3}$

$15.0 c m^{3}$

$3 c m^{3}$ .

$γ_{a} = γ_{r} - γ_{g} = (180 - 30) \times 1 0^{- 6} = 150 \times 1 0^{- 5} /^{\circ} C$
$Δ V = V_{0} γ Δ t = 1000 \times 150 \times 1 0^{- 5} \times 100$

Q. A glass flask of volume 1000cm3 is completely filled with mercury at 0∘C. The co-efficient of cubical expansion of mercury is 180×10−6/∘Cand that of glass is 30×10−6/∘C. If the flask is now placed in boiling water at 100∘ C, how much mercury will over flow ?

30cm3

18.0cm3

15.0cm3

3cm3.

γa​=γr​−γg​=(180−30)×10−6=150×10−5/∘C ΔV=V0​γΔt=1000×150×10−5×100

$30 c m^{3}$

$18.0 c m^{3}$

$15.0 c m^{3}$

$3 c m^{3}$ .

$γ_{a} = γ_{r} - γ_{g} = (180 - 30) \times 1 0^{- 6} = 150 \times 1 0^{- 5} /^{\circ} C$
$Δ V = V_{0} γ Δ t = 1000 \times 150 \times 1 0^{- 5} \times 100$