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Physics
A geostationary satellite is orbiting the Earth at a height of 6R above the surface of the earth, R being the radius of the Earth. The time period of another satellite, at a height of text2.5R from the surface of the Earth, is
Q. A geostationary satellite is orbiting the Earth at a height of
6
R
above the surface of the earth,
R
being the radius of the Earth. The time period of another satellite, at a height of
2.5
R
from the surface of the Earth, is
1414
168
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A
6
2
hour
B
6
hour
C
5
2
hour
D
10
hour
Solution:
A geostationary satellite has a time period of
T
=
24
h
r
. From Kepler's law,
T
2
∝
R
3
⇒
T
1
2
T
2
2
=
R
1
3
R
2
3
⇒
(
24
)
2
T
2
2
=
(
R
+
6
R
)
3
(
R
+
2.5
R
)
3
T
2
=
8
24
×
24
=
6
2
h
r
.