A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T. Assuming the gases to be ideal and the oxygen bond to be rigid, the total internal energy (in units of RT ) of the mixture is:

Question

A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T. Assuming the gases to be ideal and the oxygen bond to be rigid, the total internal energy (in units of RT ) of the mixture is: (A) 11 (B) 15 (C) 20 (D) 13

Tardigrade Admin · Accepted Answer

u =( f 1 n 1 RT /2)+( f 2 n 2 RT /2) u =(5/2) × 3 RT +(3 × 5 RT /2)=15 RT

Q. A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature $T$ . Assuming the gases to be ideal and the oxygen bond to be rigid, the total internal energy (in units of $RT$ ) of the mixture is:

11

15

20

13

$u = \frac{f _{1} n _{1} RT}{2} + \frac{f _{2} n _{2} RT}{2}$
$u = \frac{5}{2} \times 3 RT + \frac{3 \times 5 RT}{2} = 15 RT$

Q. A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T. Assuming the gases to be ideal and the oxygen bond to be rigid, the total internal energy (in units of RT ) of the mixture is:

11

15

20

13

u=2f1​n1​RT​+2f2​n2​RT​ u=25​×3RT+23×5RT​=15RT

Q. A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature $T$ . Assuming the gases to be ideal and the oxygen bond to be rigid, the total internal energy (in units of $RT$ ) of the mixture is:

$u = \frac{f _{1} n _{1} RT}{2} + \frac{f _{2} n _{2} RT}{2}$
$u = \frac{5}{2} \times 3 RT + \frac{3 \times 5 RT}{2} = 15 RT$