Q.
A gas is compressed at a constant pressure of 50N/m2 from a volume of 10m3 to a volume of 4m3. Energy of 100J is thus added to the gas by heating. Its internal energy is
Change in volume ΔV=V2−V1 =4−10=−6m3
As volume decreases, work is done on the gas and so it is negative W=pΔV =50×(−6)=−300J
Heat supplied Q=100J
According to first law of thermodynamics change in internal energy is ΔU=Q−W =100−(−300) =400J
It means internal energy increase by 400J