A gas is at constant pressure 4 × 105 N / m 2. When a heat energy of 2000 J is supplied to the gas, its volume changes by 3 × 10-3 m 3. What is the increase in its internal energy?

Question

A gas is at constant pressure 4 × 105 N / m 2. When a heat energy of 2000 J is supplied to the gas, its volume changes by 3 × 10-3 m 3. What is the increase in its internal energy? (A) 650 J (B) 900 J (C) 800 J (D) 400 J

Tardigrade Admin · Accepted Answer

Given, pressure, p=4 × 105 N / m 2, Δ Q=2000 J Change in volume, Δ V=3 × 10-3 m 3 Now, the work done to change volume is Δ W=p Δ V=4 × 105 × 3 × 10-3 =12 × 102=1200 J According to first law of thermodynamics, So, change in internal energy, Δ U=Δ Q-Δ W=2000-1200=800 J

Q. A gas is at constant pressure 4×105N/m2. When a heat energy of 2000J is supplied to the gas, its volume changes by 3×10−3m3. What is the increase in its internal energy?

650 J

900 J

800 J

400 J

Given, pressure, p=4×105N/m2,ΔQ=2000J Change in volume, ΔV=3×10−3m3 Now, the work done to change volume is ΔW=pΔV=4×105×3×10−3 =12×102=1200J According to first law of thermodynamics, So, change in internal energy, ΔU=ΔQ−ΔW=2000−1200=800J

Q. A gas is at constant pressure $4 \times 1 0^{5} N / m^{2}$ . When a heat energy of $2000 J$ is supplied to the gas, its volume changes by $3 \times 1 0^{- 3} m^{3}$ . What is the increase in its internal energy?