A gas cylinder containing cooking gas can withstand a pressure of 14.9 atm. The pressure gauge of cylinder indicates 12 atm at 27°C. Due to sudden fire in building the temperature starts rising. The temperature at which the cylinder will explode is

Question

A gas cylinder containing cooking gas can withstand a pressure of 14.9 atm. The pressure gauge of cylinder indicates 12 atm at 27°C. Due to sudden fire in building the temperature starts rising. The temperature at which the cylinder will explode is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(P1/T1) = (P2/T2) (12/300) = (14.9/T2) T2 = 375.5 K = 99.5° C

Q. A gas cylinder containing cooking gas can withstand a pressure of $14.9$ atm. The pressure gauge of cylinder indicates $12$ atm at $2 7^{\circ} C$ . Due to sudden fire in building the temperature starts rising. The temperature at which the cylinder will explode is

$\frac{P _{1}}{T _{1}} = \frac{P _{2}}{T _{2}}$
$\frac{12}{300} = \frac{14.9}{T _{2}}$
$T_{2} = 375.5 K = 99. 5^{\circ} C$

Q. A gas cylinder containing cooking gas can withstand a pressure of 14.9 atm. The pressure gauge of cylinder indicates 12 atm at 27∘C. Due to sudden fire in building the temperature starts rising. The temperature at which the cylinder will explode is

T1​P1​​=T2​P2​​ 30012​=T2​14.9​ T2​=375.5K=99.5∘C

Q. A gas cylinder containing cooking gas can withstand a pressure of $14.9$ atm. The pressure gauge of cylinder indicates $12$ atm at $2 7^{\circ} C$ . Due to sudden fire in building the temperature starts rising. The temperature at which the cylinder will explode is

$\frac{P _{1}}{T _{1}} = \frac{P _{2}}{T _{2}}$
$\frac{12}{300} = \frac{14.9}{T _{2}}$
$T_{2} = 375.5 K = 99. 5^{\circ} C$