Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A gamma ray photon creates an electron, positron pair. If the rest mass energy of an electron is 0.5 MeV and the total KE of the electron, positron pair is 0.78 MeV, then the energy of the gamma ray photon must be
Q. A gamma ray photon creates an electron, positron pair. If the rest mass energy of an electron is
0.5
M
e
V
and the total
K
E
of the electron, positron pair is
0.78
M
e
V
, then the energy of the gamma ray photon must be
1787
215
UPSEE
UPSEE 2014
Report Error
A
0.78
M
e
V
B
1.78
M
e
V
C
1.28
M
e
V
D
0.28
M
e
V
Solution:
Energy of
γ
-ray photon
=
0.5
+
0.5
+
0.78
=
1.78
M
e
V