A game consists of throwing rings on a peg. A player gets six rings, throws them until he gets the first success. The probability that atleast one ring remains unused if the probability of the successful throw is 0.1 is

Question

A game consists of throwing rings on a peg. A player gets six rings, throws them until he gets the first success. The probability that atleast one ring remains unused if the probability of the successful throw is 0.1 is (A) 1-((9/10))6 (B) 1-((9/10))5 (C) 1- 6 C 1((9/10))5((1/10)) (D) 1-((9/10))5((1/10))

Tardigrade Admin · Accepted Answer

Correct answer is (b) 1-((9/10))5

Q. A game consists of throwing rings on a peg. A player gets six rings, throws them until he gets the first success. The probability that atleast one ring remains unused if the probability of the successful throw is 0.1 is

$1 - (\frac{9}{10})^{6}$

$1 - (\frac{9}{10})^{5}$

$1 -^{6} C_{1} (\frac{9}{10})^{5} (\frac{1}{10})$

$1 - (\frac{9}{10})^{5} (\frac{1}{10})$

Correct answer is (b) $1 - (\frac{9}{10})^{5}$

Q. A game consists of throwing rings on a peg. A player gets six rings, throws them until he gets the first success. The probability that atleast one ring remains unused if the probability of the successful throw is 0.1 is

1−(109​)6

1−(109​)5

1−6C1​(109​)5(101​)

1−(109​)5(101​)

Correct answer is (b) 1−(109​)5

$1 - (\frac{9}{10})^{6}$

$1 - (\frac{9}{10})^{5}$

$1 -^{6} C_{1} (\frac{9}{10})^{5} (\frac{1}{10})$

$1 - (\frac{9}{10})^{5} (\frac{1}{10})$

Correct answer is (b) $1 - (\frac{9}{10})^{5}$