A galvanometer of resistance 22.8 Ω measures 1 A . How much shunt should be used, so that it can be used to measure 20 A ?

Question

A galvanometer of resistance 22.8 Ω measures 1 A . How much shunt should be used, so that it can be used to measure 20 A ? (A) 1 Ω  (B) 2 Ω  (C) 1.2 Ω  (D) 2.2 Ω

Tardigrade Admin · Accepted Answer

Shunt is a low resistance used in parallel with the galvanometer to make it ammeter.
Solution

The voltage across galvanometer = voltage across the shunt
Given,

G = 22.8Ω, i = 20 A,

i_{G} = 1 A

∴ S = \frac{1 \times 22.8}{20 - 1} = \frac{22.8}{19} = 1.2Ω

Q. A galvanometer of resistance $22.8 Ω$ measures $1 A$ . How much shunt should be used, so that it can be used to measure $20 A$ ?

$1 Ω$

$2 Ω$

$1.2 Ω$

$2.2 Ω$

Shunt is a low resistance used in parallel with the galvanometer to make it ammeter.

The voltage across galvanometer = voltage across the shunt
Given, $G = 22.8Ω, i = 20 A,$ $i_{G} = 1 A$
$∴ S = \frac{1 \times 22.8}{20 - 1} = \frac{22.8}{19} = 1.2Ω$

Q. A galvanometer of resistance 22.8Ω measures 1A . How much shunt should be used, so that it can be used to measure 20A ?

1Ω

2Ω

1.2Ω

2.2Ω