A galvanometer of resistance 20Ω shows a deflection of 10 divisions when a current of 1 mA is passed through it. If a shunt of 4 Ω is connected and there are 50 divisions on the scale, the range of the galvanometer is

Question

A galvanometer of resistance 20Ω shows a deflection of 10 divisions when a current of 1 mA is passed through it. If a shunt of 4 Ω is connected and there are 50 divisions on the scale, the range of the galvanometer is (A) 1 A (B) 3 A (C) 10 mA (D) 30 A

Tardigrade Admin · Accepted Answer

Current for 50 divisions, Ig=(1× 50/10)=5 mA ∴ (Ig/I)=(S/S+G) ⇒ I=( (S+G/S) )Ig Or I=( (4+20/4) )5mA =30 mA

Q. A galvanometer of resistance $20Ω$ shows a deflection of $10$ divisions when a current of $1 m A$ is passed through it. If a shunt of $4 Ω$ is connected and there are $50$ divisions on the scale, the range of the galvanometer is

1 A

3 A

10 mA

30 A

30 mA

Current for 50 divisions,
$I_{g} = \frac{1 \times 50}{10} = 5 m A$
$∴$ $\frac{I _{g}}{I} = \frac{S}{S + G}$
$\Rightarrow$ $I = (\frac{S + G}{S}) I_{g}$
Or $I = (\frac{4 + 20}{4}) 5 m A$
$= 30 m A$

Q. A galvanometer of resistance 20Ω shows a deflection of 10 divisions when a current of 1mA is passed through it. If a shunt of 4Ω is connected and there are 50 divisions on the scale, the range of the galvanometer is

1 A

3 A

10 mA

30 A

30 mA

Current for 50 divisions, Ig​=101×50​=5mA ∴ IIg​​=S+GS​ ⇒ I=(SS+G​)Ig​ Or I=(44+20​)5mA =30mA

Q. A galvanometer of resistance $20Ω$ shows a deflection of $10$ divisions when a current of $1 m A$ is passed through it. If a shunt of $4 Ω$ is connected and there are $50$ divisions on the scale, the range of the galvanometer is

Current for 50 divisions,
$I_{g} = \frac{1 \times 50}{10} = 5 m A$
$∴$ $\frac{I _{g}}{I} = \frac{S}{S + G}$
$\Rightarrow$ $I = (\frac{S + G}{S}) I_{g}$
Or $I = (\frac{4 + 20}{4}) 5 m A$
$= 30 m A$