Q.
A function whose graph is symmetrical about the y-axis is given by
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Relations and Functions - Part 2
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Solution:
A function whose graph is symmetrical about the y-axis must be even
Since sin x and log(x+x2+1) are odd function
therefore sin(log(x+x2+1)) must be odd.
Also, x3+x4cotxsec4x+cosec4x is an odd function.
Now, let f(x+y)=f(x)+f(y)∀x,y∈R ∴f(0+0)=f(0)+f(0)∴f(0)=0 f(x−x)=f(x)+f(−x) or 0=f(x)+f(−x)
i.e f(−x)=−f(x)∴f(x) is odd