A force 2 units acts along the line x-4=y-5. The moment of the force about the point (1, 1) along Z-axis is equal to

Question

A force 2 units acts along the line x-4=y-5. The moment of the force about the point (1, 1) along Z-axis is equal to (A)  0  (B)  (1/√2)  (C)  √2  (D)  2√2

Tardigrade Admin · Accepted Answer

Given equation of line, x-4=y-5 ⇒ x-y+1=0 ..(i) Now, moment of the force =F.d=2× (1/√2) =√2

Q. A force $2$ units acts along the line $x - 4 = y - 5.$ The moment of the force about the point $(1, 1)$ along $Z - a x i s$ is equal to

$0$

$\frac{1}{2}$

$2$

$22$

Given equation of line, $x - 4 = y - 5$
$\Rightarrow$ $x - y + 1 = 0$ ..(i)
Now, moment of the force
$= F . d = 2 \times \frac{1}{2}$
$= 2$

Q. A force 2 units acts along the line x−4=y−5. The moment of the force about the point (1,1) along Z−axis is equal to

0

2​1​

2​

22​

Given equation of line, x−4=y−5 ⇒ x−y+1=0 ..(i) Now, moment of the force =F.d=2×2​1​ =2​

Q. A force $2$ units acts along the line $x - 4 = y - 5.$ The moment of the force about the point $(1, 1)$ along $Z - a x i s$ is equal to

$0$

$\frac{1}{2}$

$2$

$22$

Given equation of line, $x - 4 = y - 5$
$\Rightarrow$ $x - y + 1 = 0$ ..(i)
Now, moment of the force
$= F . d = 2 \times \frac{1}{2}$
$= 2$