A fish at a depth of 12 cm in water is viewed by an observer on the bank of a lake. To what height the image of the fish is raised? (Refractive index of lake water = 4/3)

Question

A fish at a depth of 12 cm in water is viewed by an observer on the bank of a lake. To what height the image of the fish is raised? (Refractive index of lake water = 4/3) (A) 9 cm (B) 12 cm (C) 3.8 cm (D) 3 cm

Tardigrade Admin · Accepted Answer

Apparent rise =d(1-(1/a μw)) =12 ×(1-(3/4)) =12 × (1/4)=3 cm

Q. A fish at a depth of $12 c m$ in water is viewed by an observer on the bank of a lake. To what height the image of the fish is raised? (Refractive index of lake water $= 4/3$ )

9 cm

12 cm

3.8 cm

3 cm

Apparent rise $= d (1 - \frac{1}{a μ _{w}})$
$= 12 \times (1 - \frac{3}{4})$
$= 12 \times \frac{1}{4} = 3 c m$

Q. A fish at a depth of 12cm in water is viewed by an observer on the bank of a lake. To what height the image of the fish is raised? (Refractive index of lake water =4/3)