A fighter plane, flying horizontally with a speed 360 kmph at an altitude of 500 m drops a bomb for a target straight ahead of it on the ground. The bomb .should be dropped at what approximate distance ahead of the target? Assume that acceleration due to gravity ( g ) is 10 ms -2. Also neglect air drag

Question

A fighter plane, flying horizontally with a speed 360 kmph at an altitude of 500 m drops a bomb for a target straight ahead of it on the ground. The bomb .should be dropped at what approximate distance ahead of the target? Assume that acceleration due to gravity ( g ) is 10 ms -2. Also neglect air drag (A) 1000 m (B) 50 √5 m (C) 500 √5 m (D) 866 m

Tardigrade Admin · Accepted Answer

v =360 km / h =100 m / s . h =500 m R=u √(2 h/g)=100 × √(2 × 500/10)=1000 m

$1000 m$

$505 m$

$5005 m$

$866 m$

$v = 360 km / h = 100 m / s .$
$h = 500 m$
$R = u \frac{2 h}{g} = 100 \times \frac{2 \times 500}{10} = 1000 m$

1000m

505​m

5005​m

866m

v=360km/h=100m/s. h=500m R=ug2h​​=100×102×500​​=1000m

$1000 m$

$505 m$

$5005 m$

$866 m$

$v = 360 km / h = 100 m / s .$
$h = 500 m$
$R = u \frac{2 h}{g} = 100 \times \frac{2 \times 500}{10} = 1000 m$