A disc of a siren containing 60 holes rotates at a constant speed of 360 rpm. The emitted sound is in unison with a tuning fork of frequency

Question

A disc of a siren containing 60 holes rotates at a constant speed of 360 rpm. The emitted sound is in unison with a tuning fork of frequency (A) 10 Hz (B) 360 Hz (C) 216 Hz (D) 60 Hz

Tardigrade Admin · Accepted Answer

Speed = 360 rev/min =(360/60)rev/s=6 text rev/s ∴ Frequency =6× 60 =360 text Hz

Q. A disc of a siren containing 60 holes rotates at a constant speed of 360 rpm. The emitted sound is in unison with a tuning fork of frequency

10 Hz

360 Hz

216 Hz

60 Hz

Speed = 360 rev/min $= \frac{360}{60} re v / s = 6 re v / s$ $∴$ Frequency $= 6 \times 60$ $= 360 Hz$

Q. A disc of a siren containing 60 holes rotates at a constant speed of 360 rpm. The emitted sound is in unison with a tuning fork of frequency

10 Hz

360 Hz

216 Hz

60 Hz

Speed = 360 rev/min =60360​rev/s=6rev/s ∴ Frequency =6×60 =360Hz

Speed = 360 rev/min $= \frac{360}{60} re v / s = 6 re v / s$ $∴$ Frequency $= 6 \times 60$ $= 360 Hz$