A direct current of 4 A and an alternating current of peak value 4 A flow through resistance of 3 Ω and 2 Ω respectively. The ratio of heat produced in the two resistances in same interval of time will be :

Question

A direct current of 4 A and an alternating current of peak value 4 A flow through resistance of 3 Ω and 2 Ω respectively. The ratio of heat produced in the two resistances in same interval of time will be : (A) 3: 2 (B) 3: 1 (C) 3: 4 (D) 4: 3

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/074e90ad4da72734aa1fb58c3b269e71-.png" /> H 1= i 2 R 1 t H 2= i rms 2 R 2 t i rms =( i 0/√2) H 1=16(3) t H 2=( i 02/2) R 2 t H 2=16 t H 1: H 2=3: 1

Q. A direct current of $4 A$ and an alternating current of peak value $4 A$ flow through resistance of $3Ω$ and $2Ω$ respectively. The ratio of heat produced in the two resistances in same interval of time will be :

$3 : 2$

$3 : 1$

$3 : 4$

$4 : 3$

$H_{1} = i^{2} R_{1} t H_{2} = i_{r m s}^{2} R_{2} t {i_{r m s} = \frac{i _{0}}{2}}$
$H_{1} = 16 (3) t H_{2} = \frac{i _{0}^{2}}{2} R_{2} t$
$H_{2} = 16 t$
$H_{1} : H_{2} = 3 : 1$

Q. A direct current of 4A and an alternating current of peak value 4A flow through resistance of 3Ω and 2Ω respectively. The ratio of heat produced in the two resistances in same interval of time will be :

3:2

3:1

3:4

4:3