Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A dip needle lies initially in the magnetic meridian when it shows an angle of dip θ at a place. The dip circle is rotated through an angle x in the vertical plane and then it shows an angle of dip θ ' .Then ( tan θ '/ tan θ ) is
Q. A dip needle lies initially in the magnetic meridian when it shows an angle of dip
θ
at a place. The dip circle is rotated through an angle
x
in the vertical plane and then it shows an angle of dip
θ
′
.Then
t
a
n
θ
t
a
n
θ
′
is
1492
224
BHU
BHU 2011
Report Error
A
c
o
s
x
1
B
s
i
n
x
1
C
t
a
n
x
1
D
cos
x
Solution:
In magnetic meridian, angle of dip is given by
tan
θ
=
H
V
...(i)
When dip circle is rotated in vertical plane, then
tan
θ
′
=
H
c
o
s
x
V
∴
t
a
n
θ
t
a
n
θ
′
=
c
o
s
x
1