A diode is connected to 220 V ( rms ) ac in series with a capacitor as shown in figure. The voltage across the capacitor is

Question

A diode is connected to 220 V ( rms ) ac in series with a capacitor as shown in figure. The voltage across the capacitor is (A) 220 V (B) 110 V (C) 311.1 V (D) (220/√2) V

Tardigrade Admin · Accepted Answer

The diode D will conduct for positive half cycle of ac supply because this is forward biased. For negative half cycle of ac supply, this is reverse biased and does not conduct. So, output would be half wave rectified and for half wave rectified output V rms =(V0/2)=(200 √2/2) =(200/√2) V

Q. A diode is connected to $220 V (r m s)$ ac in series with a capacitor as shown in figure. The voltage across the capacitor is

$220 V$

$110 V$

$311.1 V$

$\frac{220}{2} V$

Q. A diode is connected to 220V(rms) ac in series with a capacitor as shown in figure. The voltage across the capacitor is

220V

110V

311.1V

2​220​V

The diode D will conduct for positive half cycle of ac supply because this is forward biased. For negative half cycle of ac supply, this is reverse biased and does not conduct. So, output would be half wave rectified and for half wave rectified output Vrms​=2V0​​=22002​​ =2​200​V

Q. A diode is connected to $220 V (r m s)$ ac in series with a capacitor as shown in figure. The voltage across the capacitor is

$220 V$

$110 V$

$311.1 V$

$\frac{220}{2} V$