A diatomic gas, having Cp=(7/2) R and C v =(5/2) R , is heated at constant pressure. The ratio dU: dQ: dW

Question

A diatomic gas, having Cp=(7/2) R and C v =(5/2) R , is heated at constant pressure. The ratio dU: dQ: dW (A) 5: 7: 3 (B) 5: 7: 2 (C) 3: 7: 2 (D) 3: 5: 2

Tardigrade Admin · Accepted Answer

d U = n C v d T d Q = n C p d T dW = PdV = nRdT (isobaric process) dU: dQ: dW: C v: C p: R =(5 R /2): (7 R /2): R =5: 7: 2

Q. A diatomic gas, having $C_{p} = \frac{7}{2} R$ and $C_{v} = \frac{5}{2} R,$ is heated at constant pressure. The ratio $d U : d Q : d W$

5: 7: 3

5: 7: 2

3: 7: 2

3: 5: 2

$d U = n C_{v} d T$
$d Q = n C_{p} d T$
$d W = P d V = n R d T$ (isobaric process)
$d U : d Q : d W : C_{v} : C_{p} : R$
$= \frac{5 R}{2} : \frac{7 R}{2} : R = 5 : 7 : 2$

Q. A diatomic gas, having Cp​=27​R and Cv​=25​R, is heated at constant pressure. The ratio dU:dQ:dW