Q.
A current of 5A is flowing at 220V in the primary coil of a transformer. If the voltage produced in the secondary coil is 2200V and 50% of power is lost, then the current in the secondary will be
Vp=220V,Vs=2200V,Ip=5A,Is=?
Power loss =50%
Efficiency of transformer (η) is defined as the ratio of output power and input power
ie, η%=Pin Pout ×100=VpIpVsIs×100 50=220×52200×Is×100 Is=0.25A