A current-carrying wire of certain length is bent to form an arc that subtends an angle θ at the centre. Let B be the magnetic field at the centre due to this wire. The correct graph between B and θ is

Question

A current-carrying wire of certain length is bent to form an arc that subtends an angle θ at the centre. Let B be the magnetic field at the centre due to this wire. The correct graph between B and θ is (A) Option 1

(B)

(C)

(D)

Tardigrade Admin · Accepted Answer

(l/R)=θ B=(μ0 i θ/2 π(2 R)) B=(μ 0 i l θ 2/4 π l2) B propto θ 2

Q. A current-carrying wire of certain length is bent to form an arc that subtends an angle $θ$ at the centre. Let $B$ be the magnetic field at the centre due to this wire. The correct graph between $B$ and $θ$ is

$\frac{l}{R} = θ$
$B = \frac{μ _{0} i θ}{2 π ( 2 R )}$
$B = \frac{μ _{0} i l θ ^{2}}{4 π l ^{2}}$
$B \propto θ^{2}$

Q. A current-carrying wire of certain length is bent to form an arc that subtends an angle θ at the centre. Let B be the magnetic field at the centre due to this wire. The correct graph between B and θ is

Rl​=θ B=2π(2R)μ0​iθ​ B=4πl2μ0​ilθ2​ B∝θ2

Q. A current-carrying wire of certain length is bent to form an arc that subtends an angle $θ$ at the centre. Let $B$ be the magnetic field at the centre due to this wire. The correct graph between $B$ and $θ$ is

$\frac{l}{R} = θ$
$B = \frac{μ _{0} i θ}{2 π ( 2 R )}$
$B = \frac{μ _{0} i l θ ^{2}}{4 π l ^{2}}$
$B \propto θ^{2}$