A cubical vessel of height 1 m is full of water. What is the amount of work done in pumping water out of the vessel? (Take g = 10 m s-2)

Question

A cubical vessel of height 1 m is full of water. What is the amount of work done in pumping water out of the vessel? (Take g = 10 m s-2) (A) 1250 J (B) 5000 J (C) 1000 J (D) 2500 J

Tardigrade Admin · Accepted Answer

The volume of water contained in the vessel would be equal to

V = l^{3} = 1^{3} m^{3} = 1 m^{3}

. Assuming water to be pure so the density of water would be equal to

d = 1000 k g / m^{3}

, hence the mass of water contained in the vessel would be equal to

m = V d = 1000 k g

. Thus, the work done would be equal to

W = m g h = 1000 \times 10 \times \frac{1}{2} = 5000 J

Q. A cubical vessel of height $1 m$ is full of water. What is the amount of work done in pumping water out of the vessel? (Take $g = 10 m s^{- 2}$ )

$1250 J$

$5000 J$

$1000 J$

$2500 J$

Q. A cubical vessel of height 1m is full of water. What is the amount of work done in pumping water out of the vessel? (Take g=10ms−2)

1250J

5000J

1000J

2500J

Q. A cubical vessel of height $1 m$ is full of water. What is the amount of work done in pumping water out of the vessel? (Take $g = 10 m s^{- 2}$ )

$1250 J$

$5000 J$

$1000 J$

$2500 J$