A cricket ball is hit at 45° to the horizontal with kinetic energy K, the kinetic energy at the highest point is :

Question

A cricket ball is hit at 45° to the horizontal with kinetic energy K, the kinetic energy at the highest point is : (A)  K  (B)  K/√2  (C)  K/2  (D)  0

Tardigrade Admin · Accepted Answer

Kinetic energy at highest point K text hight =K cos 2 45°=(K/2)

Q. A cricket ball is hit at $4 5^{\circ}$ to the horizontal with kinetic energy $K$ , the kinetic energy at the highest point is :

$K$

$K / 2$

$K /2$

$0$

Kinetic energy at highest point
$K_{hight} = K cos^{2} 4 5^{\circ} = \frac{K}{2}$

Q. A cricket ball is hit at 45∘ to the horizontal with kinetic energy K, the kinetic energy at the highest point is :

K

K/2​

K/2

0

Kinetic energy at highest point Khight ​=Kcos245∘=2K​

Q. A cricket ball is hit at $4 5^{\circ}$ to the horizontal with kinetic energy $K$ , the kinetic energy at the highest point is :

$K$

$K / 2$

$K /2$

$0$

Kinetic energy at highest point
$K_{hight} = K cos^{2} 4 5^{\circ} = \frac{K}{2}$