A conducting wire of cross-sectional area 1 cm 2 has 3 ×1023 charge carriers per m 3. If wire carries a current of 24 mA, then drift velocity of carriers is

Question

A conducting wire of cross-sectional area 1 cm 2 has 3 ×1023 charge carriers per m 3. If wire carries a current of 24 mA, then drift velocity of carriers is (A) 5 × 10-2 m / s (B) 0.5 m / s (C) 5 × 10-3 m / s (D) 5 × 10-6 m / s

Tardigrade Admin · Accepted Answer

Given, cross-sectional area, A=1 cm 2=10-4 m 2 Charge density, n=3 × 1023 m -3 Current through wire, I=24 × 10-3 A We know that, for conductors, I=n A e vd ⇒ vd=(I/n A e)=(24 × 10-3/3 × 1023 × 10-4 × 1.6 × 10-19) =(8/1.6) × 10-3=5 × 10-3 m / s

Q. A conducting wire of cross-sectional area $1 c m^{2}$ has $3 \times 1 0^{23}$ charge carriers per $m^{3}$ . If wire carries a current of $24 m A$ , then drift velocity of carriers is

$5 \times 1 0^{- 2} m / s$

$0.5 m / s$

$5 \times 1 0^{- 3} m / s$

$5 \times 1 0^{- 6} m / s$

Q. A conducting wire of cross-sectional area 1cm2 has 3×1023 charge carriers per m3. If wire carries a current of 24mA, then drift velocity of carriers is

5×10−2m/s

0.5m/s

5×10−3m/s

5×10−6m/s

Given, cross-sectional area, A=1cm2=10−4m2 Charge density, n=3×1023m−3 Current through wire, I=24×10−3A We know that, for conductors, I=nAevd​ ⇒vd​=nAeI​=3×1023×10−4×1.6×10−1924×10−3​ =1.68​×10−3=5×10−3m/s

Q. A conducting wire of cross-sectional area $1 c m^{2}$ has $3 \times 1 0^{23}$ charge carriers per $m^{3}$ . If wire carries a current of $24 m A$ , then drift velocity of carriers is

$5 \times 1 0^{- 2} m / s$

$0.5 m / s$

$5 \times 1 0^{- 3} m / s$

$5 \times 1 0^{- 6} m / s$