Question

A concave lens forms the image of an object such that the distance between the object and image is $10cm$ and the magnification produced is 1 / 4 The focal length of the lens will be

• A. -6.2 cm
• B. -4.4 cm
• C. -8.6 cm
• D. -10 cm

Answer 1

Answer: (B)

A concave lens forms virtual image $I$ of a point object $O$.
As, $m=\frac{1}{4}=\frac{v}{u}$
$\therefore u=4v$
If $v=-x,u=-4x$
Distance between object and image,

$|OI=4x-x=3x=10cm$
or $x=\frac{10}{3}cm$
$\therefore u=-\frac{40}{3}cm$ and $v=\frac{-10}{3}cm$
Using lens formula, $\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$
$\frac{1}{f}=-\frac{3}{10}+\frac{3}{40}=-\frac{9}{40}$ ;
$\therefore f=-\frac{40}{9}cm=-4.4cm$