Q. A compound $X$ decolourises $B r_{2}$ water and reacts slowly with conc. $H_{2} S O_{4}$ to give an addition product. $X$ reacts with $H B r$ to form $Y$ . $Y$ reacts with $N a O H$ to form $Z$ . On oxidation $Z$ gives hexan- $3$ -one. $X$ , $Y$ and $Z$ in the reactions are

1778 199 Hydrocarbons Report Error

A

$X = C H_{3} C H_{2} C H = C H C H_{3}$ ,
$Y = C H_{3} C H_{2} C H (B r) C H (B r) C H_{2} C H_{3}$ ,
$Z = C H_{3} C H_{2} C H_{3}$

B

$X = C H_{3} C H = C H C H_{3}$ ,
$Y = C H_{3} C H (B r) C H (B r) C H_{3}$ ,
$Z = C H_{3} C H_{2} C H_{2} O H$

C

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D

$X = C H_{3} C H_{2} C H_{2} C H = C H C H_{3}$ ,
$Y = C H_{3} C H_{2} C H_{2} C H_{2} C H_{2} C H_{2} B r$ ,
$Z = C H_{3} C H_{2} C H_{2} C H_{2} O H$

Solution:

Correct answer is (c)

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