Question

A compound has $C=40\%,H=13.33\%$ and $N=46.67\%.$ The empirical formula is:

• A. $C{H}_{4}N$
• B. $C_2{H}_{5}N$
• C. $C{H}_{2}N$
• D. $C{H}_4{N}_2$

Answer 1

Answer: (A)

Consider the compound to be made of $100g$. Convert percentile to weight in grams. then, convert wt. in grams to moles.
Moles of $C=40/12=3.33$
Moles of $H=13.33/1=13.33$
Moles of $N=46.6/14=3.33$
Now divide each mole value by lowest value of $n$ as:
$<br/>\begin{array}{l}<br/>C=3.33/3.33=1\\ <br/>H=13.33/3.33=4.00\\ <br/>N=3.33/3.33=1<br/>\end{array}<br/>$
The emperical formula is $C{H}_{4}N$.