A coil having 500 square loops of side 10 cm is placed normal to magnetic field which increases at a rate of 1 T s-1. The induced e.m.f. is

Question

A coil having 500 square loops of side 10 cm is placed normal to magnetic field which increases at a rate of 1 T s-1. The induced e.m.f. is (A) 0.1 V (B) 0.5 V (C) 1 V (D) 5 V

Tardigrade Admin · Accepted Answer

Here, area A = 500 (10/100)2 = 5 m2 (dB/dt) = 1 T s-1 Induced e.m.f |e| =(dφ/dt) =(A dB/dt) = 5× 1 = 5 volt.

Q. A coil having 500 square loops of side 10 cm is placed normal to magnetic field which increases at a rate of 1 T s $^{- 1}$ . The induced e.m.f. is

0.1 V

0.5 V

1 V

5 V

Here, area $A = 500 (10/100)^{2} = 5 m^{2}$
$\frac{d B}{d t} = 1 T s^{- 1}$
Induced e.m.f $∣ e ∣ = \frac{d ϕ}{d t} = \frac{A d B}{d t} = 5 \times 1$ = 5 volt.

Q. A coil having 500 square loops of side 10 cm is placed normal to magnetic field which increases at a rate of 1 T s−1. The induced e.m.f. is

0.1 V

0.5 V

1 V

5 V

Here, area A=500(10/100)2=5m2 dtdB​=1Ts−1 Induced e.m.f ∣e∣=dtdϕ​=dtAdB​=5×1 = 5 volt.

Q. A coil having 500 square loops of side 10 cm is placed normal to magnetic field which increases at a rate of 1 T s $^{- 1}$ . The induced e.m.f. is

Here, area $A = 500 (10/100)^{2} = 5 m^{2}$
$\frac{d B}{d t} = 1 T s^{- 1}$
Induced e.m.f $∣ e ∣ = \frac{d ϕ}{d t} = \frac{A d B}{d t} = 5 \times 1$ = 5 volt.