A closed organ pipe has a fundamental frequency of 1.5 kHz. The number of overtones that can be distinctly heard by a person with this organ pipe will be: (Assume that the highest frequency a person can hear is 20,000 Hz)

Question

A closed organ pipe has a fundamental frequency of 1.5 kHz. The number of overtones that can be distinctly heard by a person with this organ pipe will be: (Assume that the highest frequency a person can hear is 20,000 Hz) (A) 7 (B) 5 (C) 6 (D) 4

Tardigrade Admin · Accepted Answer

For closed organ pipe, resonate frequency is odd multiple of fundamental frequency.

(2 n + 1) f_{o} \leq 20, 000

(f_{o}

is fundamental frequency

= 1.5 K h z

)

n = 6

Total number of overtone that can be heared is 7. (0 to 6

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Q. A closed organ pipe has a fundamental frequency of 1.5kHz. The number of overtones that can be distinctly heard by a person with this organ pipe will be : (Assume that the highest frequency a person can hear is 20,000Hz)

7

5

6

4

For closed organ pipe, resonate frequency is odd multiple of fundamental frequency. (2n+1)fo​≤20,000 (fo​ is fundamental frequency =1.5Khz ) n=6 Total number of overtone that can be heared is 7. (0 to 6)

Q. A closed organ pipe has a fundamental frequency of $1.5 k Hz$ . The number of overtones that can be distinctly heard by a person with this organ pipe will be : (Assume that the highest frequency a person can hear is $20, 000 Hz$ )

For closed organ pipe, resonate frequency is odd multiple of fundamental frequency. $(2 n + 1) f_{o} \leq 20, 000$
$(f_{o}$ is fundamental frequency $= 1.5 K h z$ ) $n = 6$
Total number of overtone that can be heared is 7. (0 to 6 $)$