A circular coil of 10 turns and radius 10 cm is placed in a uniform magnetic field of 0.1 T normal to the plane of the coil. If the current in the coil is 5 A then the magnitude of the torque on the coil is

Question

A circular coil of 10 turns and radius 10 cm is placed in a uniform magnetic field of 0.1 T normal to the plane of the coil. If the current in the coil is 5 A then the magnitude of the torque on the coil is (A) 500 π N m (B) 0.05 π N m (C) 0.005 π N m (D) zero

Tardigrade Admin · Accepted Answer

Magnitude of torque on the coil is given as τ=|m × B| ⇒ τ=N I A B sin θ where, θ is the angle between axis of loop (normal to the loop) and direction of magnetic field. Here, θ=0 So, τ=0

Q. A circular coil of $10$ turns and radius $10 c m$ is placed in a uniform magnetic field of $0.1 T$ normal to the plane of the coil. If the current in the coil is $5 A$ then the magnitude of the torque on the coil is

$500 π N m$

$0.05 π N m$

$0.005 π N m$

zero

Magnitude of torque on the coil is given as
$τ = ∣ m \times B ∣$
$\Rightarrow τ = N I A B sin θ$
where, $θ$ is the angle between axis of loop (normal to the loop) and direction of magnetic field.
Here, $θ = 0$
So, $τ = 0$

Q. A circular coil of 10 turns and radius 10cm is placed in a uniform magnetic field of 0.1T normal to the plane of the coil. If the current in the coil is 5A then the magnitude of the torque on the coil is

500πNm

0.05πNm

0.005πNm