A charged particle moves with velocity vecv=a hati+d hatj in a magnetic field vecB=A hati+D hatj. The force acting on the particle has magnitude F. Then,

Question

A charged particle moves with velocity vecv=a hati+d hatj in a magnetic field vecB=A hati+D hatj. The force acting on the particle has magnitude F. Then, (A) F=0, if a D=d A. (B) F=0, if a D=-d A. (C) F=0, if a A=-d D. (D) F propto(a2+b2)1 / 2 ×(A2+D2)1 / 2

Tardigrade Admin · Accepted Answer

vecF propto( vecv × vecB)= hatk[a D-d A] If F=0, a D=d A

Q. A charged particle moves with velocity $v = a \hat{i} + d \hat{j}$ in a magnetic field $B = A \hat{i} + D \hat{j}$ . The force acting on the particle has magnitude $F$ . Then,

$F = 0$ , if $a D = d A$ .

$F = 0$ , if $a D = - d A$ .

$F = 0$ , if $a A = - d D$ .

$F \propto (a^{2} + b^{2})^{1/2} \times (A^{2} + D^{2})^{1/2}$

$F \propto (v \times B) = \hat{k} [a D - d A]$
If $F = 0, a D = d A$

Q. A charged particle moves with velocity v=ai^+dj^​ in a magnetic field B=Ai^+Dj^​. The force acting on the particle has magnitude F. Then,

F=0, if aD=dA.

F=0, if aD=−dA.

F=0, if aA=−dD.

F∝(a2+b2)1/2×(A2+D2)1/2