A charge Q is placed at a distance a/2 above the centre of the square surface of edge a as shown in the figure The electric flux through the square surface is :

Question

A charge Q is placed at a distance a/2 above the centre of the square surface of edge a as shown in the figure The electric flux through the square surface is : (A) (Q/ϵo) (B) (Q/ 2 ϵo) (C) (Q/ 3ϵo) (D) (Q/ 6 ϵo)

Tardigrade Admin · Accepted Answer

In the figure given in question, we can draw a cube enclosing charge

Q

at the centre, then according to gauss law, we have
flux

ϕ = \frac{Q _{aclosed}}{ε _{0}}

\Rightarrow

Electric flux through six surfaces of cube

= \frac{Q}{ε _{0}}

Therefore, electric flux through one surface

= \frac{Q}{6 ε _{0}}

.

Q. A charge $Q$ is placed at a distance $a /2$ above the centre of the square surface of edge a as shown in the figure
The electric flux through the square surface is :

$\frac{Q}{ϵ _{o}}$

$\frac{Q}{2 ϵ _{o}}$

$\frac{Q}{3 ϵ _{o}}$

$\frac{Q}{6 ϵ _{o}}$

Q. A charge Q is placed at a distance a/2 above the centre of the square surface of edge a as shown in the figure The electric flux through the square surface is :

ϵo​Q​

2ϵo​Q​

3ϵo​Q​

6ϵo​Q​

In the figure given in question, we can draw a cube enclosing charge Q at the centre, then according to gauss law, we have flux ϕ=ε0​Qaclosed ​​ ⇒ Electric flux through six surfaces of cube =ε0​Q​ Therefore, electric flux through one surface =6ε0​Q​.

Q. A charge $Q$ is placed at a distance $a /2$ above the centre of the square surface of edge a as shown in the figure
The electric flux through the square surface is :

$\frac{Q}{ϵ _{o}}$

$\frac{Q}{2 ϵ _{o}}$

$\frac{Q}{3 ϵ _{o}}$

$\frac{Q}{6 ϵ _{o}}$