A charge +q is fixed to each of three corners of a square/ On the empty corner a charge Q is placed such that there is no net electrostatic force acting on the diagonally opposite charge.Then

Question

A charge +q is fixed to each of three corners of a square/ On the empty corner a charge Q is placed such that there is no net electrostatic force acting on the diagonally opposite charge.Then (A) Q=-2q (B) q=-2√2q (C) q=-√2q (D) Q=-4q

Tardigrade Admin · Accepted Answer

(1/4 π ε0) √2 (q2/a2)+(1/4 π ε0) (Q q/(√2 q)2)=0

Q. A charge +q is fixed to each of three corners of a square/ On the empty corner a charge Q is placed such that there is no net electrostatic force acting on the diagonally opposite charge.Then

Q=-2q

$q = - 22 q$

$q = - 2 q$

Q=-4q

$\frac{1}{4 π ε _{0}} 2 \frac{q ^{2}}{a ^{2}} + \frac{1}{4 π ε _{0}} \frac{Qq}{( 2 q ) ^{2}} = 0$

Q. A charge +q is fixed to each of three corners of a square/ On the empty corner a charge Q is placed such that there is no net electrostatic force acting on the diagonally opposite charge.Then

Q=-2q

q=−22​q

q=−2​q

Q=-4q

4πε0​1​2​a2q2​+4πε0​1​(2q​)2Qq​=0

$q = - 22 q$

$q = - 2 q$

$\frac{1}{4 π ε _{0}} 2 \frac{q ^{2}}{a ^{2}} + \frac{1}{4 π ε _{0}} \frac{Qq}{( 2 q ) ^{2}} = 0$