Checking the given options one by one
(i) Q1=Q2=0.4C.
The force on Q1 due to Q2 F=kp30×10−2Q1×Q2 =k30Q1Q2×100 =k300⋅4×0.4×100 =30k×0⋅16×100
(ii) When Q1=0⋅8CQ2≈0 F=30×10−2k×Q1Q2≈0
(iii) when Q1≈0,Q2=0⋅8CF=0
(iv) Q1=0⋅2CQ2=0⋅6C F=30×10−2k⋅0⋅2×0⋅6 =30k×0⋅12×102
Thus we find that, in option(a), the force on Q1 will be maximum. ∴ correct answer is Q1=Q2=0⋅4C