A certain reaction obeys the rate equation (in the integrated form) [ C (1- n )- C 0(1- n )]=( n -1) kt where n is the order of the reaction; C 0 the initial concentration and C, the concentration after time t. What is the unit of k for n =3 :-

Question

A certain reaction obeys the rate equation (in the integrated form) [ C (1- n )- C 0(1- n )]=( n -1) kt where n is the order of the reaction; C 0 the initial concentration and C, the concentration after time t. What is the unit of k for n =3 :- (A) sec -1 (B) litre mol -1 sec -1 (C) mol litre -1 sec -1 (D) litre 2 mol -2 sec -1

Tardigrade Admin · Accepted Answer

C (1- n )- C 0(1- n )=( n -1) kt put n =3 C -2- C 0-2=2 kt concentration i.e. =( mol /ℓ) (( mol /ℓ))-2= K × second k =ℓ2 mol -2 sec -1

Q. A cetain reaction obeys the rate equation (in the integrated form) $[C^{(1 - n)} - C_{0}^{(1 - n)}] = (n - 1)$ kt where $n$ is the order of the reation; $C_{0}$ the initial concentration and C, the concentration after time $t$ . What is the unit of $k$ for $n = 3$ :-

$se c^{- 1}$

litre $m o l^{- 1} se c^{- 1}$

mol litre $^{- 1} sec^{- 1}$

litre $^{2} m o l^{- 2} se c^{- 1}$

$C^{(1 - n)} - C_{0}^{(1 - n)} = (n - 1) k t$
put $n = 3 C^{- 2} - C_{0}^{- 2} = 2 k t$
concentration i.e. $= \frac{m o l}{ℓ}$
$(\frac{m o l}{ℓ})^{- 2} = K \times$ second
$k = ℓ^{2} m o l^{- 2} se c^{- 1}$

Q. A cetain reaction obeys the rate equation (in the integrated form) [C(1−n)−C0(1−n)​]=(n−1) kt where n is the order of the reation; C0​ the initial concentration and C, the concentration after time t. What is the unit of k for n=3 :-

sec−1

litre mol−1sec−1

mol litre −1sec−1

litre 2mol−2sec−1