A certain electric motor wires that carry a current of 5 A are perpendicular to a magnetic field of 0.8 tesla. The force on each cm of wire is:

Question

A certain electric motor wires that carry a current of 5 A are perpendicular to a magnetic field of 0.8 tesla. The force on each cm of wire is: (A) 0.08 N (B) 0.06 N (C) 0.04 N (D) 0.02 N

Tardigrade Admin · Accepted Answer

F = Bil =0.8 × 5 × 20 × 10-2=0.8 N

Q. A certain electric motor wires that carry a current of 5 A are perpendicular to a magnetic field of 0.8 tesla. The force on each cm of wire is:

0.08 N

0.06 N

0.04 N

0.02 N

$F = B i l = 0.8 \times 5 \times 20 \times 1 0^{- 2} = 0.8 N$

Q. A certain electric motor wires that carry a current of 5 A are perpendicular to a magnetic field of 0.8 tesla. The force on each cm of wire is:

0.08 N

0.06 N

0.04 N

0.02 N

F=Bil=0.8×5×20×10−2=0.8N

$F = B i l = 0.8 \times 5 \times 20 \times 1 0^{- 2} = 0.8 N$