A certain current liberated 0.504 g of hydrogen in 2 h. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution? Given Atomic mass of Cu = 63.5

Question

A certain current liberated 0.504 g of hydrogen in 2 h. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution? Given Atomic mass of Cu = 63.5 (A) 12.9 g (B) 15.9 g (C) 31.7 g (D) 36.9 g

Tardigrade Admin · Accepted Answer

According to Faraday's second law, (W e i g h t o f C u/W e i g h t o f H2)=(E q . w t . o f C u/E q . w t . o f H2) ( textWeight of Cu/ text0.504)=( text63.6/2/1) ∴ Weight of Cu =15.9 g

Q. A certain current liberated 0.504 g of hydrogen in 2 h. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution? Given Atomic mass of Cu = 63.5

12.9 g

15.9 g

31.7 g

36.9 g

According to Faraday's second law,
$\frac{W e i g h t o f C u}{W e i g h t o f H _{2}} = \frac{Eq . wt . o f C u}{Eq . wt . o f H _{2}}$
$\frac{Weight of Cu}{0.504} = \frac{63.6/2}{1}$
$∴$ Weight of Cu $= 15.9 g$

Q. A certain current liberated 0.504 g of hydrogen in 2 h. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution? Given Atomic mass of Cu = 63.5

12.9 g

15.9 g

31.7 g

36.9 g

According to Faraday's second law, WeightofH2​WeightofCu​=Eq.wt.ofH2​Eq.wt.ofCu​ 0.504Weight of Cu​=163.6/2​ ∴ Weight of Cu =15.9g

According to Faraday's second law,
$\frac{W e i g h t o f C u}{W e i g h t o f H _{2}} = \frac{Eq . wt . o f C u}{Eq . wt . o f H _{2}}$
$\frac{Weight of Cu}{0.504} = \frac{63.6/2}{1}$
$∴$ Weight of Cu $= 15.9 g$