A cell has terminal voltage 2 V in open circuit and internal resistance of the given cell is 2Ω. If 4 A of current is flowing between points P and Q in the circuit and then the potential difference between P and Q is

Question

A cell has terminal voltage 2 V in open circuit and internal resistance of the given cell is 2Ω. If 4 A of current is flowing between points P and Q in the circuit and then the potential difference between P and Q is (A) 30 V (B) 26 V (C) 22 V (D) 24 V

Tardigrade Admin · Accepted Answer

Key Point Find the terminal potential difference in case of charging a battery.

According to question, it is the case of charging of battery. So, terminal potential difference is given by

TP D = V_{P} - V_{R} = E + I_{r} = 2 + (4 \times 2)

= 10 V

...(i)
Again,

V_{R} - V_{Q} = 4 \times 4 = 16 V

...(ii)
From Eqs. (i) and (ii), we get

V_{P} - V_{R} + V_{R} - V_{Q} = 10 + 16

\Rightarrow V_{P} - V_{Q} = 26 V

Q. A cell has terminal voltage $2 V$ in open circuit and internal resistance of the given cell is $2Ω$ . If $4 A$ of current is flowing between points $P$ and $Q$ in the circuit and then the potential difference between $P$ and $Q$ is

$30 V$

$26 V$

$22 V$

$24 V$

Q. A cell has terminal voltage 2V in open circuit and internal resistance of the given cell is 2Ω. If 4A of current is flowing between points P and Q in the circuit and then the potential difference between P and Q is

30V

26V

22V

24V

Q. A cell has terminal voltage $2 V$ in open circuit and internal resistance of the given cell is $2Ω$ . If $4 A$ of current is flowing between points $P$ and $Q$ in the circuit and then the potential difference between $P$ and $Q$ is

$30 V$

$26 V$

$22 V$

$24 V$