Question

A Carnot engine takes heat from a reservoir at $627^{\circ }C$ and rejects heat to a sink at $27^{\circ }C$. Its efficiency will be

• A. 3/5
• B. 1/3
• C. 2/3
• D. 200/209

Answer 1

Answer: (C)

$\eta =1-\frac{T_2}{T_1}$
$\therefore \eta =1-\frac{(27+273)}{(273+627)}$
$=1-\frac{300}{900}=\frac{600}{900}=\frac{2}{3}$