A Carnot engine absorbs 1000 J of heat energy from a reservoir at 127 ° C and rejects 600 J of heat energy during each cycle. The efficiency of the engine and temperature of the sink will be

Question

A Carnot engine absorbs 1000 J of heat energy from a reservoir at 127 ° C and rejects 600 J of heat energy during each cycle. The efficiency of the engine and temperature of the sink will be (A) 70 % and -10° C (B) 50 % and -20° C (C) 40 % and -33° C (D) 20 % and -43° C

Tardigrade Admin · Accepted Answer

Q1=1000 J Q2=600 η=1-(Q2/Q1) =40 % (T1/T2)=(Q1/Q2) (400/T2)=(1000/600) T2=240K-273=-33 ° C

Q. A Carnot engine absorbs $1000 J$ of heat energy from a reservoir at $127^{\circ} C$ and rejects $600 J$ of heat energy during each cycle. The efficiency of the engine and temperature of the sink will be

$70%$ and $- 1 0^{\circ} C$

$50%$ and $- 2 0^{\circ} C$

$40%$ and $- 3 3^{\circ} C$

$20%$ and $- 4 3^{\circ} C$

$Q_{1} = 1000 J$
$Q_{2} = 600$
$η = 1 - \frac{Q _{2}}{Q _{1}}$
$= 40%$
$\frac{T _{1}}{T _{2}} = \frac{Q _{1}}{Q _{2}}$
$\frac{400}{T _{2}} = \frac{1000}{600}$
$T_{2} = 240 K - 273 = - 33^{\circ} C$

Q. A Carnot engine absorbs 1000J of heat energy from a reservoir at 127∘C and rejects 600J of heat energy during each cycle. The efficiency of the engine and temperature of the sink will be

70% and −10∘C

50% and −20∘C

40% and −33∘C

20% and −43∘C