A Carnot engine absorbs 1000 J of heat energy from a reservoir at 127°C and rejects 600 J of heat energy during each cycle. The efficiency of engine and temperature of sink will be:

Question

A Carnot engine absorbs 1000 J of heat energy from a reservoir at 127°C and rejects 600 J of heat energy during each cycle. The efficiency of engine and temperature of sink will be: (A) 20 % and -43°C (B) 40 % and -33°C (C) 50 % and -20°C (D) 70 % and -10°C

Tardigrade Admin · Accepted Answer

Given: Q1 = 1000 J Q2 = 600 J T1=127Â°C = 400 K T2= ? η=? Efficiency of carnot engine, η=(W/Q1)×100 % or, η=(Q2-Q1/Q1)× 100 % η=(1000-600/1000)× 100 % η=40 % Now, for carnot cycle (Q2/Q1)=(T2/T1) (600/1000)=(T2/400) T2=(600×400/1000)=240 K=240-273 ∴ T2=-33Â°C

Q. A Carnot engine absorbs $1000 J$ of heat energy from a reservoir at $12 7^{\circ}$ C and rejects $600 J$ of heat energy during each cycle. The efficiency of engine and temperature of sink will be:

$20%$ and $- 4 3^{\circ}$ C

$40%$ and $- 3 3^{\circ}$ C

$50%$ and $- 2 0^{\circ}$ C

$70%$ and $- 1 0^{\circ}$ C

Q. A Carnot engine absorbs 1000J of heat energy from a reservoir at 127∘C and rejects 600J of heat energy during each cycle. The efficiency of engine and temperature of sink will be:

20% and −43∘C

40% and −33∘C

50% and −20∘C

70% and −10∘C

Q. A Carnot engine absorbs $1000 J$ of heat energy from a reservoir at $12 7^{\circ}$ C and rejects $600 J$ of heat energy during each cycle. The efficiency of engine and temperature of sink will be:

$20%$ and $- 4 3^{\circ}$ C

$40%$ and $- 3 3^{\circ}$ C

$50%$ and $- 2 0^{\circ}$ C

$70%$ and $- 1 0^{\circ}$ C