A car of mass 1000 kg moves on a circular track of radius 20 m. If the coefficient of friction is 0.64, then the maximum velocity with which the car moves is

Question

A car of mass 1000 kg moves on a circular track of radius 20 m. If the coefficient of friction is 0.64, then the maximum velocity with which the car moves is (A) 22.4 m s-1 (B) 5.6 m s-1 (C) 11.2 m s-1 (D) 6.5 m s-1

Tardigrade Admin · Accepted Answer

vmax = √μ rg = √ 0.64 × 20 × 9.8 =11.2 m s-1

Q. A car of mass 1000 kg moves on a circular track of radius 20 m. If the coefficient of friction is 0.64, then the maximum velocity with which the car moves is

$22.4 m s^{- 1}$

$5.6 m s^{- 1}$

$11.2 m s^{- 1}$

$6.5 m s^{- 1}$

$v_{ma x} = μ r g = 0.64 \times 20 \times 9.8$
$= 11.2 m s^{- 1}$

Q. A car of mass 1000 kg moves on a circular track of radius 20 m. If the coefficient of friction is 0.64, then the maximum velocity with which the car moves is

22.4ms−1

5.6ms−1

11.2ms−1

6.5ms−1

vmax​=μrg​=0.64×20×9.8​ =11.2ms−1

$22.4 m s^{- 1}$

$5.6 m s^{- 1}$

$11.2 m s^{- 1}$

$6.5 m s^{- 1}$

$v_{ma x} = μ r g = 0.64 \times 20 \times 9.8$
$= 11.2 m s^{- 1}$