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Question
Physics
A car is moving with speed 20 textm s- 1 on a circular path of radius 100 textm . Its speed is increasing at a rate of 3 textm s- 2 . The magnitude of the acceleration of the car at that moment is
Q. A car is moving with speed
20
m s
−
1
on a circular path of radius
100
m
. Its speed is increasing at a rate of
3
m s
−
2
. The magnitude of the acceleration of the car at that moment is
1844
251
NTA Abhyas
NTA Abhyas 2020
Laws of Motion
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A
1
m s
−
2
0%
B
3
m s
−
2
0%
C
4
m s
−
2
0%
D
5
m s
−
2
100%
Solution:
Given
v
=
20
m s
−
1
,
R
=
100
m
d
t
d
v
=
3
m s
−
2
a
c
=
R
v
2
=
100
(
20
)
2
=
4
(
m s
)
−
2
a
t
=
d
t
d
v
=
3
m s
−
2
a
=
a
c
2
+
a
t
2
=
4
2
+
3
2
=
5
m s
−
2