A capillary tube is immersed vertically in water and the height of the water column is x. When this arrangement is taken into a mine of depth d, the height of the water column is y. If R is the radius of earth, the ratio (x/y) is :

Question

A capillary tube is immersed vertically in water and the height of the water column is x. When this arrangement is taken into a mine of depth d, the height of the water column is y. If R is the radius of earth, the ratio (x/y) is : (A) (1-(d/R)) (B) (1-(2d/R)) (C) ((R-d/R+d)) (D) ((R+d/R-d))

Tardigrade Admin · Accepted Answer

height talances additional presence hence ρ gsx=ρ g textdepth y gs x=gs(1-d/R)y (x/y)=1-(d/R)

Q. A capillary tube is immersed vertically in water and the height of the water column is $x$ . When this arrangement is taken into a mine of depth $d$ , the height of the water column is $y$ . If $R$ is the radius of earth, the ratio $\frac{x}{y}$ is :

$(1 - \frac{d}{R})$

$(1 - \frac{2 d}{R})$

$(\frac{R - d}{R + d})$

$(\frac{R + d}{R - d})$

height talances additional presence hence

$ρ g_{s} x = ρ g_{depth} y$

$g_{s} x = g_{s} (1 - d / R) y$

$\frac{x}{y} = 1 - \frac{d}{R}$

Q. A capillary tube is immersed vertically in water and the height of the water column is x. When this arrangement is taken into a mine of depth d, the height of the water column is y. If R is the radius of earth, the ratio yx​ is :

(1−Rd​)

(1−R2d​)

(R+dR−d​)

(R−dR+d​)