A capacitor of capacitance C is charged with the help of a 200 V battery. It is then discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity 2.5 × 102 J / kg and mass 0.1 kg. If the temperature of the block rises by 0.4 K, the value of C is

Question

A capacitor of capacitance C is charged with the help of a 200 V battery. It is then discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity 2.5 × 102 J / kg and mass 0.1 kg. If the temperature of the block rises by 0.4 K, the value of C is (A) 500 F (B) 500 μ F (C) 50 F (D) 50 μ F

Tardigrade Admin · Accepted Answer

(1/2) × C ×(200)2 =2.5 × 102 × 0.1 × 0.4 2 × 104 C=1 × 10 C=(1/2 × 103)=500 μ F

$500 F$

$500 μ F$

$50 F$

$50 μ F$

$\frac{1}{2} \times C \times (200)^{2}$
$= 2.5 \times 1 0^{2} \times 0.1 \times 0.4$
$2 \times 1 0^{4} C = 1 \times 10$
$C = \frac{1}{2 \times 1 0 ^{3}} = 500 μ F$

Q. A capacitor of capacitance C is charged with the help of a 200V battery. It is then discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity 2.5×102J/kg and mass 0.1kg. If the temperature of the block rises by 0.4K, the value of C is

500F

500μF

50F

50μF

21​×C×(200)2 =2.5×102×0.1×0.4 2×104C=1×10 C=2×1031​=500μF

$500 F$

$500 μ F$

$50 F$

$50 μ F$

$\frac{1}{2} \times C \times (200)^{2}$
$= 2.5 \times 1 0^{2} \times 0.1 \times 0.4$
$2 \times 1 0^{4} C = 1 \times 10$
$C = \frac{1}{2 \times 1 0 ^{3}} = 500 μ F$